Chapter 2 Techniques of Solving Equations and Inequalities
- \[ \abs{ab}=\abs{a}\abs{b} \]
- \[ \left|{\frac{a}{b}}\right|=\frac{\abs{a}}{\abs{b}}(b\ne0) \]
- The triangle inequality \[ \abs{a+b}\leq\abs{a}+\abs{b} \]
- \[ \abs{a-b}\geq\abs{a}-\abs{b} \]
- Add the same expression to both sides of a given equation, or subtract the same expression from both sides.
- Multiply or divide both sides of a given equation by the same nonzero expression.
- Interchange the left-hand and right-hand sides of a given equation.
- Simplify algebraic expressions that appear on either side of a given equation.
- Read the problem carefully and determine what the question is asking you to find. Ask yourself what is known and what is unknown.
- Assign one of the unknowns the variable $x$ (or any other letter you wish), and express each of the other unknowns in terms of $x.$ When appropriate, draw a picture of the situation being described.
- Develop an equation that relates the known and unknown quanitites. This relationship may be given by an established formula or may require some intuition.
- Solve this equation for $x.$ Use this solution to answer the question the problem asked.
- Check your answer by making certain it satisfies the conditions of the problem.
If a mixture of $b$ liters contains $r\%$ of a certain ingredient, then the amount $a$ of that ingredient (in liters) in the mixture is given. \[ a=\frac{r}{100}\cdot b \]
total cost = variable costs + fixed costs
total revenue = price per unit $\times$ number of units sold
profit = total revenue – total cost
Formulas to find the
If it takes $t$ hours to complete a certain job when working at a constant rate of speed, then $1/t$ of the job will be done in 1 hour.
Case 1
If $b^2-4ac\gt0,$ then $\sqrt{b^2-4ac}$ is a real number and the quadratic formula gives two distinct real roots: \[ \frac{-b+\sqrt{b^2-4ac}}{2a} \] and \[ \frac{-b-\sqrt{b^2-4ac}}{2a}. \] If $a,b,c$ are rational numbers and $b^2-4ac$ is the square of a rational number, then these two distinct real roots are rational numbers. Otherwise, the roots are irrational numbers.
Case 2
If $b^2-4ac\lt0,$ then $\sqrt{b^2-4ac}$ is a
pure imaginary number and the quadratic formula
gives two
Case 3
If $b^2-4ac=0,$ then $\sqrt{b^2-4ac}$ is zero
and the quadratic formula gives only one real root:
\[
-\frac{b}{2a}.
\]
The quantity $-\frac{b}{2a}$ is called
Discriminant | Nature of roots |
---|---|
$b^2-4ac\gt0$ | Two distinct real roots |
$b^2-4ac\lt0$ | Two complex conjugate roots |
$b^2-4ac=0$ | One real root of multiplicity two |
Case 1
If $k\gt0,$ $m>0,$ $m$ even, then $x^m=k$ has two real solutions, $\pm\sqrt[m]{k}.$
Example: $x^4=10\Rightarrow x=\pm\sqrt[4]{10}$
Case 2
If $k\lt0,$ $m>0,$ $m$ even, then $x^m=k$ has no real solution.
Example: $x^4=-10$ has no real solution.
Case 3
If $k\in\R,$ $m>0,$ $m$ odd, then $x^m=k$ has one real solution $\sqrt[m]{k}.$
Example: $x^5=18\Rightarrow x =\sqrt[5]{-18} =-\sqrt[5]{18}$
To solve
However, does raising both sides of an equation to a positive integer power generate equivalent equations?
Consider \[ x=k\quad\text{ where }\quad k\in\R \] If we raise both sides to the $n\text{th}$ power, we obtain \[ x^n=k^n. \] There are two possibilities when solving this equation.
Case 1: $n\gt0,$ $n$ odd
\[ x=\sqrt[n]{k^n}\\ x=k \] equivalent equations are generated.
Case 2: $n\gt0,$ $n$ even
\[
x=\pm\sqrt[n]{k^n}\\
x=\pm k
\]
equivalent equations are not generated.
since $-k$ does not satisfy the original equation.
$-k$ is called an
Therefore, when raising both sides of an equation to a positive even integer power, check all solutions in the original equation to eliminate extraneous roots.
Equations that contain the unknown in a radicand
are called
- Isolate the radical on one side of the equation.
- Eliminate the radical by raising both sides of the equation to the power equal to the index of the radical.
- If the index is even, check solutions for extraneous roots.
If one side of an equation can be factored into
a product of algebraic expressions and the other
side of the equation equals zero, then we may
use the zero product property to help solve
these
Occurs when a quadratic-type equation, $au^2+bu+c=0,$ $a\ne0$ and $u$ an algebraic expression, has the characteristic that the exponent of $x$ in the first and second terms are in a $2:1$ ratio. For example, in the quadratic type equation \[ x^6-9x^3+8=0 \] the exponents $6$ and $3$ are in the ratio $2:1.$
Put it in the quadratic form $au^2+bu+c=0$ and solve it using the methods for solving a quadratic equation.
An
Any portion of the real number line that corresponds
geometrically to a line segment is called a
Inequality | Solution Interval | Graph |
---|---|---|
|
||
$x\gt a$ | $(a,\infty)$ | |
$x\ge a$ | $[a,\infty)$ | |
$x\lt a$ | $(-\infty, a)$ | |
$x\le a$ | $(-\infty, a]$ | |
$-\infty\lt x \lt\infty$ | $(-\infty,\infty)$ | |
|
||
$a\lt x\lt b$ | $(a,b)$ | |
|
||
$a\le x\le b$ | $[a,b]$ | |
|
||
$a\lt x\le b$ | $(a,b]$ | |
$a\le x\lt b$ | $[a,b)$ |
- Add or subtract the same quanitity on both sides of the given inequality.
- Multiply or divide both sides of a given inequality by the same positive quantity.
-
Multiply or divide both sides of a given
inequality by the same negative quantity
and reverse the inequality (that is
change $\lt$ to $\gt$, $\gt$ to $\lt$
$\le$ to $\ge$, $\ge$ to
$\le$.) - Interchange the left-hand and right-hand sides of a given inequality, and reverse the inequality.
- Simplify algebraic expressions that appear on either side of a given inequality.
- Multiplying both sides of an inequality reverses the sense of the inequality.
- Interchanging left-hand and right-hand sides of an inequality reverses the sense of the inequality.
- To solve a double inequality in which the unknown appears only in the middle member, generate an equivalent double inequality by performing operations on all three members.
- To solve a double inequality in which the unknown appears in more than one member, write the double inequality $a\lt b\lt c$ as two inequalities \[ a\lt b\quad\text{ and }\quad b\lt c \] The solution set for such a double inequality is all real numbers common to the solution intervals of both $a\lt b$ and $b\lt c.$